Solve 2y+8/y-1=3

$$\frac { 2 y + 8 } { y } - 1 = 3$$

Solve for y

$$y=4$$

Steps for Solving Linear Equation

Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by y.

$$2y+8+y\left(-1\right)=3y$$

Combine 2y and y\left(-1\right) to get y.

$$y+8=3y$$

Subtract 3y from both sides.

$$y+8-3y=0$$

Combine y and -3y to get -2y.

$$-2y+8=0$$

Subtract 8 from both sides. Anything subtracted from zero gives its negation.

$$-2y=-8$$

Divide both sides by -2.

$$y=\frac{-8}{-2}$$

Divide -8 by -2 to get 4.

$$y=4$$