Solve for x
x=\frac{y+12}{2}
Solve for y
y=2\left(x-6\right)
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2x-y=3\times 4
Multiply both sides by 4.
2x-y=12
Multiply 3 and 4 to get 12.
2x=12+y
Add y to both sides.
2x=y+12
The equation is in standard form.
\frac{2x}{2}=\frac{y+12}{2}
Divide both sides by 2.
x=\frac{y+12}{2}
Dividing by 2 undoes the multiplication by 2.
x=\frac{y}{2}+6
Divide 12+y by 2.
2x-y=3\times 4
Multiply both sides by 4.
2x-y=12
Multiply 3 and 4 to get 12.
-y=12-2x
Subtract 2x from both sides.
\frac{-y}{-1}=\frac{12-2x}{-1}
Divide both sides by -1.
y=\frac{12-2x}{-1}
Dividing by -1 undoes the multiplication by -1.
y=2x-12
Divide 12-2x by -1.
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