Solve 2x/y+10/3x-20

$$\frac { 2 x } { y + 10 } / 3 x - 20$$

Evaluate

$$\frac{2\left(x^{2}-30y-300\right)}{3\left(y+10\right)}$$

Short Solution Steps

Express \frac{\frac{2x}{y+10}}{3} as a single fraction.

$$\frac{2x}{\left(y+10\right)\times 3}x-20$$

Express \frac{2x}{\left(y+10\right)\times 3}x as a single fraction.

$$\frac{2xx}{\left(y+10\right)\times 3}-20$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 20 times \frac{\left(y+10\right)\times 3}{\left(y+10\right)\times 3}.

$$\frac{2xx}{\left(y+10\right)\times 3}-\frac{20\left(y+10\right)\times 3}{\left(y+10\right)\times 3}$$

Since \frac{2xx}{\left(y+10\right)\times 3} and \frac{20\left(y+10\right)\times 3}{\left(y+10\right)\times 3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2xx-20\left(y+10\right)\times 3}{\left(y+10\right)\times 3}$$

Do the multiplications in 2xx-20\left(y+10\right)\times 3.

$$\frac{2x^{2}-60y-600}{\left(y+10\right)\times 3}$$

Expand \left(y+10\right)\times 3.

$$\frac{2x^{2}-60y-600}{3y+30}$$

Factor

$$\frac{2\left(x^{2}-30y-300\right)}{3\left(y+10\right)}$$