Solve 2x/3+9x/3=

$$\frac { 2 x } { 3 } + \frac { 9 x } { 3 } =$$

Evaluate

$$\frac{11x}{3}$$

Short Solution Steps

Divide 9x by 3 to get 3x.

$$\frac{2x}{3}+3x$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 3x times \frac{3}{3}.

$$\frac{2x}{3}+\frac{3\times 3x}{3}$$

Since \frac{2x}{3} and \frac{3\times 3x}{3} have the same denominator, add them by adding their numerators.

$$\frac{2x+3\times 3x}{3}$$

Do the multiplications in 2x+3\times 3x.

$$\frac{2x+9x}{3}$$

Combine like terms in 2x+9x.

$$\frac{11x}{3}$$

Differentiate w.r.t. x

$$\frac{11}{3} = 3\frac{2}{3} = 3.6666666666666665$$