Solve 2x*2/2x+1=22x/2x-1

$$\frac { 2 x \cdot 2 } { 2 x + 1 } = 2 \frac { 2 x } { 2 x - 1 }$$

Solve for x

$$x=0$$

Steps for Solving Linear Equation

Variable x cannot be equal to any of the values -\frac{1}{2},\frac{1}{2} since division by zero is not defined. Multiply both sides of the equation by \left(2x-1\right)\left(2x+1\right), the least common multiple of 2x+1,2x-1.

$$\left(2x-1\right)\times 2x\times 2=2\left(2x+1\right)\times 2x$$

Multiply 2 and 2 to get 4.

$$\left(2x-1\right)\times 4x=2\left(2x+1\right)\times 2x$$

Use the distributive property to multiply 2x-1 by 4.

$$\left(8x-4\right)x=2\left(2x+1\right)\times 2x$$

Use the distributive property to multiply 8x-4 by x.

$$8x^{2}-4x=2\left(2x+1\right)\times 2x$$

Multiply 2 and 2 to get 4.

$$8x^{2}-4x=4\left(2x+1\right)x$$

Use the distributive property to multiply 4 by 2x+1.

$$8x^{2}-4x=\left(8x+4\right)x$$

Use the distributive property to multiply 8x+4 by x.

$$8x^{2}-4x=8x^{2}+4x$$

Subtract 8x^{2} from both sides.

$$8x^{2}-4x-8x^{2}=4x$$

Combine 8x^{2} and -8x^{2} to get 0.

$$-4x=4x$$

Subtract 4x from both sides.

$$-4x-4x=0$$

Combine -4x and -4x to get -8x.

$$-8x=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since -8 is not equal to 0, x must be equal to 0.

$$x=0$$