Skip to main content
Solve for x
Tick mark Image
Graph

Similar Problems from Web Search

Share

\left(6x-1\right)\left(2x+5\right)=\left(4x+1\right)\left(3x+5\right)
Variable x cannot be equal to any of the values -\frac{1}{4},\frac{1}{6} since division by zero is not defined. Multiply both sides of the equation by \left(6x-1\right)\left(4x+1\right), the least common multiple of 4x+1,6x-1.
12x^{2}+28x-5=\left(4x+1\right)\left(3x+5\right)
Use the distributive property to multiply 6x-1 by 2x+5 and combine like terms.
12x^{2}+28x-5=12x^{2}+23x+5
Use the distributive property to multiply 4x+1 by 3x+5 and combine like terms.
12x^{2}+28x-5-12x^{2}=23x+5
Subtract 12x^{2} from both sides.
28x-5=23x+5
Combine 12x^{2} and -12x^{2} to get 0.
28x-5-23x=5
Subtract 23x from both sides.
5x-5=5
Combine 28x and -23x to get 5x.
5x=5+5
Add 5 to both sides.
5x=10
Add 5 and 5 to get 10.
x=\frac{10}{5}
Divide both sides by 5.
x=2
Divide 10 by 5 to get 2.