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x-1>0 x-1<0
Denominator x-1 cannot be zero since division by zero is not defined. There are two cases.
x>1
Consider the case when x-1 is positive. Move -1 to the right hand side.
2x+4\geq 5\left(x-1\right)
The initial inequality does not change the direction when multiplied by x-1 for x-1>0.
2x+4\geq 5x-5
Multiply out the right hand side.
2x-5x\geq -4-5
Move the terms containing x to the left hand side and all other terms to the right hand side.
-3x\geq -9
Combine like terms.
x\leq 3
Divide both sides by -3. Since -3 is negative, the inequality direction is changed.
x\in (1,3]
Consider condition x>1 specified above.
x<1
Now consider the case when x-1 is negative. Move -1 to the right hand side.
2x+4\leq 5\left(x-1\right)
The initial inequality changes the direction when multiplied by x-1 for x-1<0.
2x+4\leq 5x-5
Multiply out the right hand side.
2x-5x\leq -4-5
Move the terms containing x to the left hand side and all other terms to the right hand side.
-3x\leq -9
Combine like terms.
x\geq 3
Divide both sides by -3. Since -3 is negative, the inequality direction is changed.
x\in \emptyset
Consider condition x<1 specified above.
x\in (1,3]
The final solution is the union of the obtained solutions.