Solve for x
x=-\frac{1}{5}=-0.2
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\left(x+3\right)\left(2x+3\right)=\left(2x-1\right)\left(x-5\right)
Variable x cannot be equal to any of the values -3,\frac{1}{2} since division by zero is not defined. Multiply both sides of the equation by \left(2x-1\right)\left(x+3\right), the least common multiple of 2x-1,x+3.
2x^{2}+9x+9=\left(2x-1\right)\left(x-5\right)
Use the distributive property to multiply x+3 by 2x+3 and combine like terms.
2x^{2}+9x+9=2x^{2}-11x+5
Use the distributive property to multiply 2x-1 by x-5 and combine like terms.
2x^{2}+9x+9-2x^{2}=-11x+5
Subtract 2x^{2} from both sides.
9x+9=-11x+5
Combine 2x^{2} and -2x^{2} to get 0.
9x+9+11x=5
Add 11x to both sides.
20x+9=5
Combine 9x and 11x to get 20x.
20x=5-9
Subtract 9 from both sides.
20x=-4
Subtract 9 from 5 to get -4.
x=\frac{-4}{20}
Divide both sides by 20.
x=-\frac{1}{5}
Reduce the fraction \frac{-4}{20} to lowest terms by extracting and canceling out 4.
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