Solve 2r^2-8r-42/8*1/2r+6

$$\frac { 2 r ^ { 2 } - 8 r - 42 } { 8 } \times \frac { 1 } { 2 r + 6 }$$

Evaluate

$$\frac{r-7}{8}$$

Short Solution Steps

Multiply \frac{2r^{2}-8r-42}{8} times \frac{1}{2r+6} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2r^{2}-8r-42}{8\left(2r+6\right)}$$

Factor the expressions that are not already factored.

$$\frac{2\left(r-7\right)\left(r+3\right)}{2\times 8\left(r+3\right)}$$

Cancel out 2\left(r+3\right) in both numerator and denominator.

$$\frac{r-7}{8}$$

Expand

$$\frac{r-7}{8}$$

Short Solution Steps

Multiply \frac{2r^{2}-8r-42}{8} times \frac{1}{2r+6} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2r^{2}-8r-42}{8\left(2r+6\right)}$$

Factor the expressions that are not already factored.

$$\frac{2\left(r-7\right)\left(r+3\right)}{2\times 8\left(r+3\right)}$$

Cancel out 2\left(r+3\right) in both numerator and denominator.

$$\frac{r-7}{8}$$