Solve 2k-1/k(1-2k)=?

$$\frac { 2 k - 1 } { k } ( 1 - 2 k ) = ?$$

Evaluate

$$-\frac{\left(2k-1\right)^{2}}{k}$$

Short Solution Steps

Express \frac{2k-1}{k}\left(1-2k\right) as a single fraction.

$$\frac{\left(2k-1\right)\left(1-2k\right)}{k}$$

Apply the distributive property by multiplying each term of 2k-1 by each term of 1-2k.

$$\frac{2k-4k^{2}-1+2k}{k}$$

Combine 2k and 2k to get 4k.

$$\frac{4k-4k^{2}-1}{k}$$

Expand

$$-4k+4-\frac{1}{k}$$

Short Solution Steps

Express \frac{2k-1}{k}\left(1-2k\right) as a single fraction.

$$\frac{\left(2k-1\right)\left(1-2k\right)}{k}$$

Apply the distributive property by multiplying each term of 2k-1 by each term of 1-2k.

$$\frac{2k-4k^{2}-1+2k}{k}$$

Combine 2k and 2k to get 4k.

$$\frac{4k-4k^{2}-1}{k}$$