Solve 2a/21b^2*7a/6b

$$\frac { 2 a } { 21 b ^ { 2 } } \times \frac { 7 a } { 6 b }$$

Evaluate

$$\frac{a^{2}}{9b^{3}}$$

Solution Steps

Multiply \frac{2a}{21b^{2}} times \frac{7a}{6b} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2a\times 7a}{21b^{2}\times 6b}$$

Cancel out 2\times 7 in both numerator and denominator.

$$\frac{aa}{3\times 3bb^{2}}$$

Multiply a and a to get a^{2}.

$$\frac{a^{2}}{3\times 3bb^{2}}$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$\frac{a^{2}}{3\times 3b^{3}}$$

Multiply 3 and 3 to get 9.

$$\frac{a^{2}}{9b^{3}}$$

Differentiate w.r.t. a

$$\frac{2a}{9b^{3}}$$