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Solve for P
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Solve for p
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5\left(2P-3\right)=2\left(2p-3\right)
Multiply both sides of the equation by 5\left(2p-3\right), the least common multiple of 2p-3,5.
10P-15=2\left(2p-3\right)
Use the distributive property to multiply 5 by 2P-3.
10P-15=4p-6
Use the distributive property to multiply 2 by 2p-3.
10P=4p-6+15
Add 15 to both sides.
10P=4p+9
Add -6 and 15 to get 9.
\frac{10P}{10}=\frac{4p+9}{10}
Divide both sides by 10.
P=\frac{4p+9}{10}
Dividing by 10 undoes the multiplication by 10.
P=\frac{2p}{5}+\frac{9}{10}
Divide 4p+9 by 10.
5\left(2P-3\right)=2\left(2p-3\right)
Variable p cannot be equal to \frac{3}{2} since division by zero is not defined. Multiply both sides of the equation by 5\left(2p-3\right), the least common multiple of 2p-3,5.
10P-15=2\left(2p-3\right)
Use the distributive property to multiply 5 by 2P-3.
10P-15=4p-6
Use the distributive property to multiply 2 by 2p-3.
4p-6=10P-15
Swap sides so that all variable terms are on the left hand side.
4p=10P-15+6
Add 6 to both sides.
4p=10P-9
Add -15 and 6 to get -9.
\frac{4p}{4}=\frac{10P-9}{4}
Divide both sides by 4.
p=\frac{10P-9}{4}
Dividing by 4 undoes the multiplication by 4.
p=\frac{5P}{2}-\frac{9}{4}
Divide 10P-9 by 4.
p=\frac{5P}{2}-\frac{9}{4}\text{, }p\neq \frac{3}{2}
Variable p cannot be equal to \frac{3}{2}.