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15\left(2-\frac{1}{3}\times 5\right)=4x
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 15x, the least common multiple of x,15.
15\left(2-\frac{5}{3}\right)=4x
Multiply \frac{1}{3} and 5 to get \frac{5}{3}.
15\left(\frac{6}{3}-\frac{5}{3}\right)=4x
Convert 2 to fraction \frac{6}{3}.
15\times \frac{6-5}{3}=4x
Since \frac{6}{3} and \frac{5}{3} have the same denominator, subtract them by subtracting their numerators.
15\times \frac{1}{3}=4x
Subtract 5 from 6 to get 1.
\frac{15}{3}=4x
Multiply 15 and \frac{1}{3} to get \frac{15}{3}.
5=4x
Divide 15 by 3 to get 5.
4x=5
Swap sides so that all variable terms are on the left hand side.
x=\frac{5}{4}
Divide both sides by 4.