Solve 2/t^2-4=3/t^2-2t

$$\frac { 2 } { t ^ { 2 } - 4 } = \frac { 3 } { t ^ { 2 } - 2 t }$$

Solve for t

$$t=-6$$

Steps for Solving Linear Equation

Variable t cannot be equal to any of the values -2,0,2 since division by zero is not defined. Multiply both sides of the equation by t\left(t-2\right)\left(t+2\right), the least common multiple of t^{2}-4,t^{2}-2t.

$$t\times 2=\left(t+2\right)\times 3$$

Use the distributive property to multiply t+2 by 3.

$$t\times 2=3t+6$$

Subtract 3t from both sides.

$$t\times 2-3t=6$$

Combine t\times 2 and -3t to get -t.

$$-t=6$$

Multiply both sides by -1.

$$t=-6$$