Solve 2/7[3+1/3]

$$\frac { 2 } { 7 } [ 3 + \frac { 1 } { 3 } ]$$

Evaluate

$$\frac{20}{21}\approx 0.952380952$$

Solution Steps

Convert 3 to fraction \frac{9}{3}.

$$\frac{2}{7}\left(\frac{9}{3}+\frac{1}{3}\right)$$

Since \frac{9}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{2}{7}\times \frac{9+1}{3}$$

Add 9 and 1 to get 10.

$$\frac{2}{7}\times \frac{10}{3}$$

Multiply \frac{2}{7} times \frac{10}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 10}{7\times 3}$$

Do the multiplications in the fraction \frac{2\times 10}{7\times 3}.

$$\frac{20}{21}$$

Factor

$$\frac{2 ^ {2} \cdot 5}{3 \cdot 7} = 0.9523809523809523$$