Solve 2/7=a/3+x

$$\frac { 2 } { 7 } = \frac { a } { 3 + x }$$

Solve for a

$$a=\frac{2\left(x+3\right)}{7}$$

$$x\neq -3$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 7\left(x+3\right), the least common multiple of 7,3+x.

$$2\left(x+3\right)=7a$$

Use the distributive property to multiply 2 by x+3.

$$2x+6=7a$$

Swap sides so that all variable terms are on the left hand side.

$$7a=2x+6$$

Divide both sides by 7.

$$\frac{7a}{7}=\frac{2x+6}{7}$$

Dividing by 7 undoes the multiplication by 7.

$$a=\frac{2x+6}{7}$$

Solve for x

$$x=\frac{7a}{2}-3$$

$$a\neq 0$$

Steps for Solving Linear Equation

Variable x cannot be equal to -3 since division by zero is not defined. Multiply both sides of the equation by 7\left(x+3\right), the least common multiple of 7,3+x.

$$2\left(x+3\right)=7a$$

Use the distributive property to multiply 2 by x+3.

$$2x+6=7a$$

Subtract 6 from both sides.

$$2x=7a-6$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{7a-6}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{7a-6}{2}$$

Divide 7a-6 by 2.

$$x=\frac{7a}{2}-3$$

Variable x cannot be equal to -3.

$$x=\frac{7a}{2}-3\text{, }x\neq -3$$