Solve 2/5m-Bp=2/5y

$$\frac { 2 } { 5 } m - B p = \frac { 2 } { 5 } y$$

Solve for B (complex solution)

$$\left\{\begin{matrix}B=\frac{2\left(m-y\right)}{5p}\text{, }&p\neq 0\\B\in \mathrm{C}\text{, }&m=y\text{ and }p=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract \frac{2}{5}m from both sides.

$$-Bp=\frac{2}{5}y-\frac{2}{5}m$$

The equation is in standard form.

$$\left(-p\right)B=\frac{2y-2m}{5}$$

Divide both sides by -p.

$$\frac{\left(-p\right)B}{-p}=\frac{2y-2m}{5\left(-p\right)}$$

Dividing by -p undoes the multiplication by -p.

$$B=\frac{2y-2m}{5\left(-p\right)}$$

Divide \frac{2y-2m}{5} by -p.

$$B=-\frac{2\left(y-m\right)}{5p}$$

Solve for B

$$\left\{\begin{matrix}B=\frac{2\left(m-y\right)}{5p}\text{, }&p\neq 0\\B\in \mathrm{R}\text{, }&m=y\text{ and }p=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract \frac{2}{5}m from both sides.

$$-Bp=\frac{2}{5}y-\frac{2}{5}m$$

The equation is in standard form.

$$\left(-p\right)B=\frac{2y-2m}{5}$$

Divide both sides by -p.

$$\frac{\left(-p\right)B}{-p}=\frac{2y-2m}{5\left(-p\right)}$$

Dividing by -p undoes the multiplication by -p.

$$B=\frac{2y-2m}{5\left(-p\right)}$$

Divide \frac{2y-2m}{5} by -p.

$$B=-\frac{2\left(y-m\right)}{5p}$$

Solve for m

$$m=\frac{5Bp}{2}+y$$

Steps for Solving Linear Equation

Add Bp to both sides.

$$\frac{2}{5}m=\frac{2}{5}y+Bp$$

The equation is in standard form.

$$\frac{2}{5}m=Bp+\frac{2y}{5}$$

Divide both sides of the equation by \frac{2}{5}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{2}{5}m}{\frac{2}{5}}=\frac{Bp+\frac{2y}{5}}{\frac{2}{5}}$$

Dividing by \frac{2}{5} undoes the multiplication by \frac{2}{5}.

$$m=\frac{Bp+\frac{2y}{5}}{\frac{2}{5}}$$

Divide \frac{2y}{5}+Bp by \frac{2}{5} by multiplying \frac{2y}{5}+Bp by the reciprocal of \frac{2}{5}.

$$m=\frac{5Bp}{2}+y$$