Solve 2/5+23/10+11/3=

$$\frac { 2 } { 5 } + 2 \frac { 3 } { 10 } + 1 \frac { 1 } { 3 } =$$

Evaluate

$$\frac{121}{30}\approx 4.033333333$$

Solution Steps

Multiply 2 and 10 to get 20.

$$\frac{2}{5}+\frac{20+3}{10}+\frac{1\times 3+1}{3}$$

Add 20 and 3 to get 23.

$$\frac{2}{5}+\frac{23}{10}+\frac{1\times 3+1}{3}$$

Least common multiple of 5 and 10 is 10. Convert \frac{2}{5} and \frac{23}{10} to fractions with denominator 10.

$$\frac{4}{10}+\frac{23}{10}+\frac{1\times 3+1}{3}$$

Since \frac{4}{10} and \frac{23}{10} have the same denominator, add them by adding their numerators.

$$\frac{4+23}{10}+\frac{1\times 3+1}{3}$$

Add 4 and 23 to get 27.

$$\frac{27}{10}+\frac{1\times 3+1}{3}$$

Multiply 1 and 3 to get 3.

$$\frac{27}{10}+\frac{3+1}{3}$$

Add 3 and 1 to get 4.

$$\frac{27}{10}+\frac{4}{3}$$

Least common multiple of 10 and 3 is 30. Convert \frac{27}{10} and \frac{4}{3} to fractions with denominator 30.

$$\frac{81}{30}+\frac{40}{30}$$

Since \frac{81}{30} and \frac{40}{30} have the same denominator, add them by adding their numerators.

$$\frac{81+40}{30}$$

Add 81 and 40 to get 121.

$$\frac{121}{30}$$

Factor

$$\frac{11 ^ {2}}{2 \cdot 3 \cdot 5} = 4\frac{1}{30} = 4.033333333333333$$