Solve 2/4-8/4+4/8

$$\frac { 2 } { 4 } - \frac { 8 } { 4 } + \frac { 4 } { 8 }$$

Evaluate

$$-1$$

Solution Steps

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{1}{2}-\frac{8}{4}+\frac{4}{8}$$

Divide 8 by 4 to get 2.

$$\frac{1}{2}-2+\frac{4}{8}$$

Convert 2 to fraction \frac{4}{2}.

$$\frac{1}{2}-\frac{4}{2}+\frac{4}{8}$$

Since \frac{1}{2} and \frac{4}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-4}{2}+\frac{4}{8}$$

Subtract 4 from 1 to get -3.

$$-\frac{3}{2}+\frac{4}{8}$$

Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.

$$-\frac{3}{2}+\frac{1}{2}$$

Since -\frac{3}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{-3+1}{2}$$

Add -3 and 1 to get -2.

$$\frac{-2}{2}$$

Divide -2 by 2 to get -1.

$$-1$$

Factor

$$-1$$