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Solve for x (complex solution)
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\frac{2}{3}x-4=\frac{1}{3}\times 2x+\frac{1}{3}\left(-12\right)
Use the distributive property to multiply \frac{1}{3} by 2x-12.
\frac{2}{3}x-4=\frac{2}{3}x+\frac{1}{3}\left(-12\right)
Multiply \frac{1}{3} and 2 to get \frac{2}{3}.
\frac{2}{3}x-4=\frac{2}{3}x+\frac{-12}{3}
Multiply \frac{1}{3} and -12 to get \frac{-12}{3}.
\frac{2}{3}x-4=\frac{2}{3}x-4
Divide -12 by 3 to get -4.
\frac{2}{3}x-4-\frac{2}{3}x=-4
Subtract \frac{2}{3}x from both sides.
-4=-4
Combine \frac{2}{3}x and -\frac{2}{3}x to get 0.
\text{true}
Compare -4 and -4.
x\in \mathrm{C}
This is true for any x.
\frac{2}{3}x-4=\frac{1}{3}\times 2x+\frac{1}{3}\left(-12\right)
Use the distributive property to multiply \frac{1}{3} by 2x-12.
\frac{2}{3}x-4=\frac{2}{3}x+\frac{1}{3}\left(-12\right)
Multiply \frac{1}{3} and 2 to get \frac{2}{3}.
\frac{2}{3}x-4=\frac{2}{3}x+\frac{-12}{3}
Multiply \frac{1}{3} and -12 to get \frac{-12}{3}.
\frac{2}{3}x-4=\frac{2}{3}x-4
Divide -12 by 3 to get -4.
\frac{2}{3}x-4-\frac{2}{3}x=-4
Subtract \frac{2}{3}x from both sides.
-4=-4
Combine \frac{2}{3}x and -\frac{2}{3}x to get 0.
\text{true}
Compare -4 and -4.
x\in \mathrm{R}
This is true for any x.