Solve 2/3x-3/2(1-3-x/3)=2-3x/6

$$\frac { 2 } { 3 } x - \frac { 3 } { 2 } ( 1 - \frac { 3 - x } { 3 } ) = \frac { 2 - 3 x } { 6 }$$

Solve for x

$$x=\frac{1}{2}=0.5$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6, the least common multiple of 3,2,6.

$$4x-9\left(1-\frac{3-x}{3}\right)=2-3x$$

Divide each term of 3-x by 3 to get 1-\frac{1}{3}x.

$$4x-9\left(1-\left(1-\frac{1}{3}x\right)\right)=2-3x$$

To find the opposite of 1-\frac{1}{3}x, find the opposite of each term.

$$4x-9\left(1-1-\left(-\frac{1}{3}x\right)\right)=2-3x$$

The opposite of -\frac{1}{3}x is \frac{1}{3}x.

$$4x-9\left(1-1+\frac{1}{3}x\right)=2-3x$$

Subtract 1 from 1 to get 0.

$$4x-9\times \frac{1}{3}x=2-3x$$

Multiply 9 and \frac{1}{3} to get \frac{9}{3}.

$$4x-\frac{9}{3}x=2-3x$$

Divide 9 by 3 to get 3.

$$4x-3x=2-3x$$

Combine 4x and -3x to get x.

$$x=2-3x$$

Add 3x to both sides.

$$x+3x=2$$

Combine x and 3x to get 4x.

$$4x=2$$

Divide both sides by 4.

$$x=\frac{2}{4}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$x=\frac{1}{2}$$