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\frac{2}{3}x-\frac{1}{4}=\frac{1}{3}-\frac{6}{3}
Convert 2 to fraction \frac{6}{3}.
\frac{2}{3}x-\frac{1}{4}=\frac{1-6}{3}
Since \frac{1}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.
\frac{2}{3}x-\frac{1}{4}=-\frac{5}{3}
Subtract 6 from 1 to get -5.
\frac{2}{3}x=-\frac{5}{3}+\frac{1}{4}
Add \frac{1}{4} to both sides.
\frac{2}{3}x=-\frac{20}{12}+\frac{3}{12}
Least common multiple of 3 and 4 is 12. Convert -\frac{5}{3} and \frac{1}{4} to fractions with denominator 12.
\frac{2}{3}x=\frac{-20+3}{12}
Since -\frac{20}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.
\frac{2}{3}x=-\frac{17}{12}
Add -20 and 3 to get -17.
x=-\frac{17}{12}\times \frac{3}{2}
Multiply both sides by \frac{3}{2}, the reciprocal of \frac{2}{3}.
x=\frac{-17\times 3}{12\times 2}
Multiply -\frac{17}{12} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.
x=\frac{-51}{24}
Do the multiplications in the fraction \frac{-17\times 3}{12\times 2}.
x=-\frac{17}{8}
Reduce the fraction \frac{-51}{24} to lowest terms by extracting and canceling out 3.