Solve 2/3x+1/4=1/6x-1/4

$$\frac { 2 } { 3 } x + \frac { 1 } { 4 } = \frac { 1 } { 6 } x - \frac { 1 } { 4 }$$

Solve for x

$$x=-1$$

Steps for Solving Linear Equation

Subtract \frac{1}{6}x from both sides.

$$\frac{2}{3}x+\frac{1}{4}-\frac{1}{6}x=-\frac{1}{4}$$

Combine \frac{2}{3}x and -\frac{1}{6}x to get \frac{1}{2}x.

$$\frac{1}{2}x+\frac{1}{4}=-\frac{1}{4}$$

Subtract \frac{1}{4} from both sides.

$$\frac{1}{2}x=-\frac{1}{4}-\frac{1}{4}$$

Since -\frac{1}{4} and \frac{1}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{2}x=\frac{-1-1}{4}$$

Subtract 1 from -1 to get -2.

$$\frac{1}{2}x=\frac{-2}{4}$$

Reduce the fraction \frac{-2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{1}{2}x=-\frac{1}{2}$$

Multiply both sides by 2, the reciprocal of \frac{1}{2}.

$$x=-\frac{1}{2}\times 2$$

Cancel out 2 and 2.

$$x=-1$$