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\frac{2}{3}w+\frac{2}{3}=\frac{2}{3}+\frac{4}{3}w
Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.
\frac{2}{3}w+\frac{2}{3}-\frac{4}{3}w=\frac{2}{3}
Subtract \frac{4}{3}w from both sides.
-\frac{2}{3}w+\frac{2}{3}=\frac{2}{3}
Combine \frac{2}{3}w and -\frac{4}{3}w to get -\frac{2}{3}w.
-\frac{2}{3}w=\frac{2}{3}-\frac{2}{3}
Subtract \frac{2}{3} from both sides.
-\frac{2}{3}w=0
Subtract \frac{2}{3} from \frac{2}{3} to get 0.
w=0
Product of two numbers is equal to 0 if at least one of them is 0. Since -\frac{2}{3} is not equal to 0, w must be equal to 0.