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x-\frac{3}{4}=\frac{1}{12}\times \frac{3}{2}
Multiply both sides by \frac{3}{2}, the reciprocal of \frac{2}{3}.
x-\frac{3}{4}=\frac{1\times 3}{12\times 2}
Multiply \frac{1}{12} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.
x-\frac{3}{4}=\frac{3}{24}
Do the multiplications in the fraction \frac{1\times 3}{12\times 2}.
x-\frac{3}{4}=\frac{1}{8}
Reduce the fraction \frac{3}{24} to lowest terms by extracting and canceling out 3.
x=\frac{1}{8}+\frac{3}{4}
Add \frac{3}{4} to both sides.
x=\frac{1}{8}+\frac{6}{8}
Least common multiple of 8 and 4 is 8. Convert \frac{1}{8} and \frac{3}{4} to fractions with denominator 8.
x=\frac{1+6}{8}
Since \frac{1}{8} and \frac{6}{8} have the same denominator, add them by adding their numerators.
x=\frac{7}{8}
Add 1 and 6 to get 7.