Solve 2/3*9+4*3-8=-6+12-8=-2

$$\frac { 2 } { 3 } \cdot 9 + 4 \cdot 3 - 8 = - 6 + 12 - 8 = - 2$$

Verify

Solution Steps

Express \frac{2}{3}\times 9 as a single fraction.

$$\frac{2\times 9}{3}+4\times 3-8=-6+12-8\text{ and }-6+12-8=-2$$

Multiply 2 and 9 to get 18.

$$\frac{18}{3}+4\times 3-8=-6+12-8\text{ and }-6+12-8=-2$$

Divide 18 by 3 to get 6.

$$6+4\times 3-8=-6+12-8\text{ and }-6+12-8=-2$$

Multiply 4 and 3 to get 12.

$$6+12-8=-6+12-8\text{ and }-6+12-8=-2$$

Add 6 and 12 to get 18.

$$18-8=-6+12-8\text{ and }-6+12-8=-2$$

Subtract 8 from 18 to get 10.

$$10=-6+12-8\text{ and }-6+12-8=-2$$

Add -6 and 12 to get 6.

$$10=6-8\text{ and }-6+12-8=-2$$

Subtract 8 from 6 to get -2.

$$10=-2\text{ and }-6+12-8=-2$$

Compare 10 and -2.

$$\text{false}\text{ and }-6+12-8=-2$$

Add -6 and 12 to get 6.

$$\text{false}\text{ and }6-8=-2$$

Subtract 8 from 6 to get -2.

$$\text{false}\text{ and }-2=-2$$

Compare -2 and -2.

$$\text{false}\text{ and }\text{true}$$

The conjunction of \text{false} and \text{true} is \text{false}.

$$\text{false}$$