Solve 2/11*0.04+4/11*0.05+5/11*0.03

$$\frac { 2 } { 11 } \times 0.04 + \frac { 4 } { 11 } \times 0.05 + \frac { 5 } { 11 } \times 0.03$$

Evaluate

$$\frac{43}{1100}\approx 0.039090909$$

Solution Steps

Convert decimal number 0.04 to fraction \frac{4}{100}. Reduce the fraction \frac{4}{100} to lowest terms by extracting and canceling out 4.

$$\frac{2}{11}\times \frac{1}{25}+\frac{4}{11}\times 0.05+\frac{5}{11}\times 0.03$$

Multiply \frac{2}{11} times \frac{1}{25} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 1}{11\times 25}+\frac{4}{11}\times 0.05+\frac{5}{11}\times 0.03$$

Do the multiplications in the fraction \frac{2\times 1}{11\times 25}.

$$\frac{2}{275}+\frac{4}{11}\times 0.05+\frac{5}{11}\times 0.03$$

Convert decimal number 0.05 to fraction \frac{5}{100}. Reduce the fraction \frac{5}{100} to lowest terms by extracting and canceling out 5.

$$\frac{2}{275}+\frac{4}{11}\times \frac{1}{20}+\frac{5}{11}\times 0.03$$

Multiply \frac{4}{11} times \frac{1}{20} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2}{275}+\frac{4\times 1}{11\times 20}+\frac{5}{11}\times 0.03$$

Do the multiplications in the fraction \frac{4\times 1}{11\times 20}.

$$\frac{2}{275}+\frac{4}{220}+\frac{5}{11}\times 0.03$$

Reduce the fraction \frac{4}{220} to lowest terms by extracting and canceling out 4.

$$\frac{2}{275}+\frac{1}{55}+\frac{5}{11}\times 0.03$$

Least common multiple of 275 and 55 is 275. Convert \frac{2}{275} and \frac{1}{55} to fractions with denominator 275.

$$\frac{2}{275}+\frac{5}{275}+\frac{5}{11}\times 0.03$$

Since \frac{2}{275} and \frac{5}{275} have the same denominator, add them by adding their numerators.

$$\frac{2+5}{275}+\frac{5}{11}\times 0.03$$

Add 2 and 5 to get 7.

$$\frac{7}{275}+\frac{5}{11}\times 0.03$$

Convert decimal number 0.03 to fraction \frac{3}{100}.

$$\frac{7}{275}+\frac{5}{11}\times \frac{3}{100}$$

Multiply \frac{5}{11} times \frac{3}{100} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7}{275}+\frac{5\times 3}{11\times 100}$$

Do the multiplications in the fraction \frac{5\times 3}{11\times 100}.

$$\frac{7}{275}+\frac{15}{1100}$$

Reduce the fraction \frac{15}{1100} to lowest terms by extracting and canceling out 5.

$$\frac{7}{275}+\frac{3}{220}$$

Least common multiple of 275 and 220 is 1100. Convert \frac{7}{275} and \frac{3}{220} to fractions with denominator 1100.

$$\frac{28}{1100}+\frac{15}{1100}$$

Since \frac{28}{1100} and \frac{15}{1100} have the same denominator, add them by adding their numerators.

$$\frac{28+15}{1100}$$

Add 28 and 15 to get 43.

$$\frac{43}{1100}$$

Factor

$$\frac{43}{11 \cdot 2 ^ {2} \cdot 5 ^ {2}} = 0.03909090909090909$$