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\frac{2\times 3\sqrt{7}}{\sqrt{18}}
Factor 63=3^{2}\times 7. Rewrite the square root of the product \sqrt{3^{2}\times 7} as the product of square roots \sqrt{3^{2}}\sqrt{7}. Take the square root of 3^{2}.
\frac{6\sqrt{7}}{\sqrt{18}}
Multiply 2 and 3 to get 6.
\frac{6\sqrt{7}}{3\sqrt{2}}
Factor 18=3^{2}\times 2. Rewrite the square root of the product \sqrt{3^{2}\times 2} as the product of square roots \sqrt{3^{2}}\sqrt{2}. Take the square root of 3^{2}.
\frac{2\sqrt{7}}{\sqrt{2}}
Cancel out 3 in both numerator and denominator.
\frac{2\sqrt{7}\sqrt{2}}{\left(\sqrt{2}\right)^{2}}
Rationalize the denominator of \frac{2\sqrt{7}}{\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{2\sqrt{7}\sqrt{2}}{2}
The square of \sqrt{2} is 2.
\frac{2\sqrt{14}}{2}
To multiply \sqrt{7} and \sqrt{2}, multiply the numbers under the square root.
\sqrt{14}
Cancel out 2 and 2.