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\frac{2\sqrt{6}}{3\times 2\sqrt{2}}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
\frac{2\sqrt{6}}{6\sqrt{2}}
Multiply 3 and 2 to get 6.
\frac{\sqrt{6}}{3\sqrt{2}}
Cancel out 2 in both numerator and denominator.
\frac{\sqrt{6}\sqrt{2}}{3\left(\sqrt{2}\right)^{2}}
Rationalize the denominator of \frac{\sqrt{6}}{3\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{\sqrt{6}\sqrt{2}}{3\times 2}
The square of \sqrt{2} is 2.
\frac{\sqrt{2}\sqrt{3}\sqrt{2}}{3\times 2}
Factor 6=2\times 3. Rewrite the square root of the product \sqrt{2\times 3} as the product of square roots \sqrt{2}\sqrt{3}.
\frac{2\sqrt{3}}{3\times 2}
Multiply \sqrt{2} and \sqrt{2} to get 2.
\frac{2\sqrt{3}}{6}
Multiply 3 and 2 to get 6.
\frac{1}{3}\sqrt{3}
Divide 2\sqrt{3} by 6 to get \frac{1}{3}\sqrt{3}.