Solve 2^2-3^2/sqrt{9}

$$\frac { 2 ^ { 2 } - 3 ^ { 2 } } { \sqrt { 9 } }$$

Evaluate

$$-\frac{5}{3}\approx -1.666666667$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\frac{4-3^{2}}{\sqrt{9}}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{4-9}{\sqrt{9}}$$

Subtract 9 from 4 to get -5.

$$\frac{-5}{\sqrt{9}}$$

Calculate the square root of 9 and get 3.

$$\frac{-5}{3}$$

Fraction \frac{-5}{3} can be rewritten as -\frac{5}{3} by extracting the negative sign.

$$-\frac{5}{3}$$

Factor

$$-\frac{5}{3} = -1\frac{2}{3} = -1.6666666666666667$$