Solve 2^2*(6^2-7*3)/frac{4^3-2*3^3{2}}

$$\frac { 2 ^ { 2 } \cdot ( 6 ^ { 2 } - 7 \cdot 3 ) } { \frac { 4 ^ { 3 } - 2 \cdot 3 ^ { 3 } } { 2 } }$$

Evaluate

$$12$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\frac{4\left(6^{2}-7\times 3\right)}{\frac{4^{3}-2\times 3^{3}}{2}}$$

Calculate 6 to the power of 2 and get 36.

$$\frac{4\left(36-7\times 3\right)}{\frac{4^{3}-2\times 3^{3}}{2}}$$

Multiply 7 and 3 to get 21.

$$\frac{4\left(36-21\right)}{\frac{4^{3}-2\times 3^{3}}{2}}$$

Subtract 21 from 36 to get 15.

$$\frac{4\times 15}{\frac{4^{3}-2\times 3^{3}}{2}}$$

Multiply 4 and 15 to get 60.

$$\frac{60}{\frac{4^{3}-2\times 3^{3}}{2}}$$

Calculate 4 to the power of 3 and get 64.

$$\frac{60}{\frac{64-2\times 3^{3}}{2}}$$

Calculate 3 to the power of 3 and get 27.

$$\frac{60}{\frac{64-2\times 27}{2}}$$

Multiply 2 and 27 to get 54.

$$\frac{60}{\frac{64-54}{2}}$$

Subtract 54 from 64 to get 10.

$$\frac{60}{\frac{10}{2}}$$

Divide 10 by 2 to get 5.

$$\frac{60}{5}$$

Divide 60 by 5 to get 12.

$$12$$

Factor

$$2^{2}\times 3$$