Solve 2^-2+2^-3/2^-4

$$\frac { 2 ^ { - 2 } + 2 ^ { - 3 } } { 2 ^ { - 4 } }$$

Evaluate

$$6$$

Solution Steps

Calculate 2 to the power of -2 and get \frac{1}{4}.

$$\frac{\frac{1}{4}+2^{-3}}{2^{-4}}$$

Calculate 2 to the power of -3 and get \frac{1}{8}.

$$\frac{\frac{1}{4}+\frac{1}{8}}{2^{-4}}$$

Add \frac{1}{4} and \frac{1}{8} to get \frac{3}{8}.

$$\frac{\frac{3}{8}}{2^{-4}}$$

Calculate 2 to the power of -4 and get \frac{1}{16}.

$$\frac{\frac{3}{8}}{\frac{1}{16}}$$

Divide \frac{3}{8} by \frac{1}{16} by multiplying \frac{3}{8} by the reciprocal of \frac{1}{16}.

$$\frac{3}{8}\times 16$$

Multiply \frac{3}{8} and 16 to get 6.

$$6$$

Factor

$$2\times 3$$