Solve 2[-(3+1-4)*(7-3+1)]/(5*2)*(4-1)=

$$\frac { 2 [ - ( 3 + 1 - 4 ) \times ( 7 - 3 + 1 ) ] } { ( 5 \times 2 ) \times ( 4 - 1 ) } =$$

Evaluate

$$0$$

Solution Steps

Cancel out 2 in both numerator and denominator.

$$\frac{\left(-\left(1+3-4\right)\right)\left(1+7-3\right)}{5\left(4-1\right)}$$

Add 1 and 3 to get 4.

$$\frac{\left(-\left(4-4\right)\right)\left(1+7-3\right)}{5\left(4-1\right)}$$

Subtract 4 from 4 to get 0.

$$\frac{0\left(1+7-3\right)}{5\left(4-1\right)}$$

Add 1 and 7 to get 8.

$$\frac{0\left(8-3\right)}{5\left(4-1\right)}$$

Subtract 3 from 8 to get 5.

$$\frac{0\times 5}{5\left(4-1\right)}$$

Multiply 0 and 5 to get 0.

$$\frac{0}{5\left(4-1\right)}$$

Subtract 1 from 4 to get 3.

$$\frac{0}{5\times 3}$$

Multiply 5 and 3 to get 15.

$$\frac{0}{15}$$

Zero divided by any non-zero number gives zero.

$$0$$

Factor

$$0$$