Solve 2+7/10/frac{1{10}-1}=

$$\frac { 2 + \frac { 7 } { 10 } } { \frac { 1 } { 10 } - 1 } =$$

Evaluate

$$-3$$

Solution Steps

Convert 2 to fraction \frac{20}{10}.

$$\frac{\frac{20}{10}+\frac{7}{10}}{\frac{1}{10}-1}$$

Since \frac{20}{10} and \frac{7}{10} have the same denominator, add them by adding their numerators.

$$\frac{\frac{20+7}{10}}{\frac{1}{10}-1}$$

Add 20 and 7 to get 27.

$$\frac{\frac{27}{10}}{\frac{1}{10}-1}$$

Convert 1 to fraction \frac{10}{10}.

$$\frac{\frac{27}{10}}{\frac{1}{10}-\frac{10}{10}}$$

Since \frac{1}{10} and \frac{10}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{27}{10}}{\frac{1-10}{10}}$$

Subtract 10 from 1 to get -9.

$$\frac{\frac{27}{10}}{-\frac{9}{10}}$$

Divide \frac{27}{10} by -\frac{9}{10} by multiplying \frac{27}{10} by the reciprocal of -\frac{9}{10}.

$$\frac{27}{10}\left(-\frac{10}{9}\right)$$

Multiply \frac{27}{10} times -\frac{10}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{27\left(-10\right)}{10\times 9}$$

Do the multiplications in the fraction \frac{27\left(-10\right)}{10\times 9}.

$$\frac{-270}{90}$$

Divide -270 by 90 to get -3.

$$-3$$

Factor

$$-3$$