Solve 18/256+3/16

$$\frac { 18 } { 256 } + \frac { 3 } { 16 }$$

Evaluate

$$\frac{33}{128}=0.2578125$$

Solution Steps

Reduce the fraction \frac{18}{256} to lowest terms by extracting and canceling out 2.

$$\frac{9}{128}+\frac{3}{16}$$

Least common multiple of 128 and 16 is 128. Convert \frac{9}{128} and \frac{3}{16} to fractions with denominator 128.

$$\frac{9}{128}+\frac{24}{128}$$

Since \frac{9}{128} and \frac{24}{128} have the same denominator, add them by adding their numerators.

$$\frac{9+24}{128}$$

Add 9 and 24 to get 33.

$$\frac{33}{128}$$

Factor

$$\frac{3 \cdot 11}{2 ^ {7}} = 0.2578125$$