Solve 17y/7y-3

$$\frac { 17 y } { 7 y - 3 }$$

Differentiate w.r.t. y

$$-\frac{51}{\left(7y-3\right)^{2}}$$

Steps Using Derivative Rule for Quotient

For any two differentiable functions, the derivative of the quotient of two functions is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the denominator squared.

$$\frac{\left(7y^{1}-3\right)\frac{\mathrm{d}}{\mathrm{d}y}(17y^{1})-17y^{1}\frac{\mathrm{d}}{\mathrm{d}y}(7y^{1}-3)}{\left(7y^{1}-3\right)^{2}}$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$\frac{\left(7y^{1}-3\right)\times 17y^{1-1}-17y^{1}\times 7y^{1-1}}{\left(7y^{1}-3\right)^{2}}$$

Do the arithmetic.

$$\frac{\left(7y^{1}-3\right)\times 17y^{0}-17y^{1}\times 7y^{0}}{\left(7y^{1}-3\right)^{2}}$$

Expand using distributive property.

$$\frac{7y^{1}\times 17y^{0}-3\times 17y^{0}-17y^{1}\times 7y^{0}}{\left(7y^{1}-3\right)^{2}}$$

To multiply powers of the same base, add their exponents.

$$\frac{7\times 17y^{1}-3\times 17y^{0}-17\times 7y^{1}}{\left(7y^{1}-3\right)^{2}}$$

Do the arithmetic.

$$\frac{119y^{1}-51y^{0}-119y^{1}}{\left(7y^{1}-3\right)^{2}}$$

Combine like terms.

$$\frac{\left(119-119\right)y^{1}-51y^{0}}{\left(7y^{1}-3\right)^{2}}$$

Subtract 119 from 119.

$$\frac{-51y^{0}}{\left(7y^{1}-3\right)^{2}}$$

For any term t, t^{1}=t.

$$\frac{-51y^{0}}{\left(7y-3\right)^{2}}$$

For any term t except 0, t^{0}=1.

$$\frac{-51}{\left(7y-3\right)^{2}}$$

Evaluate

$$\frac{17y}{7y-3}$$