Solve 17x^2/18y^3*49xz/51x^3y

$$\frac { 17 x ^ { 2 } } { 18 y ^ { 3 } } \times \frac { 49 x z } { 51 x ^ { 3 } y }$$

Evaluate

$$\frac{49z}{54y^{4}}$$

Solution Steps

Cancel out x in both numerator and denominator.

$$\frac{17x^{2}}{18y^{3}}\times \frac{49z}{51yx^{2}}$$

Multiply \frac{17x^{2}}{18y^{3}} times \frac{49z}{51yx^{2}} by multiplying numerator times numerator and denominator times denominator.

$$\frac{17x^{2}\times 49z}{18y^{3}\times 51yx^{2}}$$

Cancel out 17x^{2} in both numerator and denominator.

$$\frac{49z}{3\times 18yy^{3}}$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$\frac{49z}{3\times 18y^{4}}$$

Multiply 3 and 18 to get 54.

$$\frac{49z}{54y^{4}}$$

Differentiate w.r.t. z

$$\frac{49}{54y^{4}}$$