Solve 17/40-2/10div13/5

$$\frac { 17 } { 40 } - \frac { 2 } { 10 } \div 1 \frac { 3 } { 5 }$$

Evaluate

$$\frac{3}{10}=0.3$$

Solution Steps

Divide \frac{2}{10} by \frac{1\times 5+3}{5} by multiplying \frac{2}{10} by the reciprocal of \frac{1\times 5+3}{5}.

$$\frac{17}{40}-\frac{2\times 5}{10\left(1\times 5+3\right)}$$

Cancel out 2\times 5 in both numerator and denominator.

$$\frac{17}{40}-\frac{1}{3+5}$$

Add 3 and 5 to get 8.

$$\frac{17}{40}-\frac{1}{8}$$

Least common multiple of 40 and 8 is 40. Convert \frac{17}{40} and \frac{1}{8} to fractions with denominator 40.

$$\frac{17}{40}-\frac{5}{40}$$

Since \frac{17}{40} and \frac{5}{40} have the same denominator, subtract them by subtracting their numerators.

$$\frac{17-5}{40}$$

Subtract 5 from 17 to get 12.

$$\frac{12}{40}$$

Reduce the fraction \frac{12}{40} to lowest terms by extracting and canceling out 4.

$$\frac{3}{10}$$

Factor

$$\frac{3}{2 \cdot 5} = 0.3$$