Solve 17/15*17/15+2/15*2/15-frac{17}{15}*frac{4}{15}quadfrac{1}{4214}

$$\frac { 17 } { 15 } \times \frac { 17 } { 15 } + \frac { 2 } { 15 } \times \frac { 2 } { 15 } - \frac { 17 } { 15 } \times \frac { 4 } { 15 } \quad \frac { 1 } { 4214 }$$

Evaluate

$$\frac{617317}{474075}\approx 1.302150504$$

Solution Steps

Multiply \frac{17}{15} times \frac{17}{15} by multiplying numerator times numerator and denominator times denominator.

$$\frac{17\times 17}{15\times 15}+\frac{2}{15}\times \frac{2}{15}-\frac{17}{15}\times \frac{4}{15}\times \frac{1}{4214}$$

Do the multiplications in the fraction \frac{17\times 17}{15\times 15}.

$$\frac{289}{225}+\frac{2}{15}\times \frac{2}{15}-\frac{17}{15}\times \frac{4}{15}\times \frac{1}{4214}$$

Multiply \frac{2}{15} times \frac{2}{15} by multiplying numerator times numerator and denominator times denominator.

$$\frac{289}{225}+\frac{2\times 2}{15\times 15}-\frac{17}{15}\times \frac{4}{15}\times \frac{1}{4214}$$

Do the multiplications in the fraction \frac{2\times 2}{15\times 15}.

$$\frac{289}{225}+\frac{4}{225}-\frac{17}{15}\times \frac{4}{15}\times \frac{1}{4214}$$

Since \frac{289}{225} and \frac{4}{225} have the same denominator, add them by adding their numerators.

$$\frac{289+4}{225}-\frac{17}{15}\times \frac{4}{15}\times \frac{1}{4214}$$

Add 289 and 4 to get 293.

$$\frac{293}{225}-\frac{17}{15}\times \frac{4}{15}\times \frac{1}{4214}$$

Multiply \frac{17}{15} times \frac{4}{15} by multiplying numerator times numerator and denominator times denominator.

$$\frac{293}{225}-\frac{17\times 4}{15\times 15}\times \frac{1}{4214}$$

Do the multiplications in the fraction \frac{17\times 4}{15\times 15}.

$$\frac{293}{225}-\frac{68}{225}\times \frac{1}{4214}$$

Multiply \frac{68}{225} times \frac{1}{4214} by multiplying numerator times numerator and denominator times denominator.

$$\frac{293}{225}-\frac{68\times 1}{225\times 4214}$$

Do the multiplications in the fraction \frac{68\times 1}{225\times 4214}.

$$\frac{293}{225}-\frac{68}{948150}$$

Reduce the fraction \frac{68}{948150} to lowest terms by extracting and canceling out 2.

$$\frac{293}{225}-\frac{34}{474075}$$

Least common multiple of 225 and 474075 is 474075. Convert \frac{293}{225} and \frac{34}{474075} to fractions with denominator 474075.

$$\frac{617351}{474075}-\frac{34}{474075}$$

Since \frac{617351}{474075} and \frac{34}{474075} have the same denominator, subtract them by subtracting their numerators.

$$\frac{617351-34}{474075}$$

Subtract 34 from 617351 to get 617317.

$$\frac{617317}{474075}$$

Factor

$$\frac{59 \cdot 10463}{3 ^ {2} \cdot 5 ^ {2} \cdot 7 ^ {2} \cdot 43} = 1\frac{143242}{474075} = 1.3021505036122976$$