Solve 16xy^9/14xy^3=?

$$\frac { 16 x y ^ { 9 } } { 14 x y ^ { 3 } } = ?$$

Evaluate

$$\frac{8y^{6}}{7}$$

Steps Using Quotient of Powers Property

Use the rules of exponents to simplify the expression.

$$\frac{16^{1}x^{1}y^{9}}{14^{1}x^{1}y^{3}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{16^{1}}{14^{1}}x^{1-1}y^{9-3}$$

Subtract 1 from 1.

$$\frac{16^{1}}{14^{1}}x^{0}y^{9-3}$$

For any number a except 0, a^{0}=1.

$$\frac{16^{1}}{14^{1}}y^{9-3}$$

Subtract 3 from 9.

$$\frac{16^{1}}{14^{1}}y^{6}$$

Reduce the fraction \frac{16}{14} to lowest terms by extracting and canceling out 2.

$$\frac{8}{7}y^{6}$$

Differentiate w.r.t. y

$$\frac{48y^{5}}{7}$$