Solve 16/3x+1/3=22/3x

$$\frac { 16 } { 3 } x + \frac { 1 } { 3 } = \frac { 22 } { 3 } x$$

Solve for x

$$x=\frac{1}{6}\approx 0.166666667$$

Steps for Solving Linear Equation

Subtract \frac{22}{3}x from both sides.

$$\frac{16}{3}x+\frac{1}{3}-\frac{22}{3}x=0$$

Combine \frac{16}{3}x and -\frac{22}{3}x to get -2x.

$$-2x+\frac{1}{3}=0$$

Subtract \frac{1}{3} from both sides. Anything subtracted from zero gives its negation.

$$-2x=-\frac{1}{3}$$

Divide both sides by -2.

$$x=\frac{-\frac{1}{3}}{-2}$$

Express \frac{-\frac{1}{3}}{-2} as a single fraction.

$$x=\frac{-1}{3\left(-2\right)}$$

Multiply 3 and -2 to get -6.

$$x=\frac{-1}{-6}$$

Fraction \frac{-1}{-6} can be simplified to \frac{1}{6} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{1}{6}$$