Solve 16/3-1/2*64/9

$$\frac { 16 } { 3 } - \frac { 1 } { 2 } \times \frac { 64 } { 9 }$$

Evaluate

$$\frac{16}{9}\approx 1.777777778$$

Solution Steps

Multiply \frac{1}{2} times \frac{64}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{16}{3}-\frac{1\times 64}{2\times 9}$$

Do the multiplications in the fraction \frac{1\times 64}{2\times 9}.

$$\frac{16}{3}-\frac{64}{18}$$

Reduce the fraction \frac{64}{18} to lowest terms by extracting and canceling out 2.

$$\frac{16}{3}-\frac{32}{9}$$

Least common multiple of 3 and 9 is 9. Convert \frac{16}{3} and \frac{32}{9} to fractions with denominator 9.

$$\frac{48}{9}-\frac{32}{9}$$

Since \frac{48}{9} and \frac{32}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{48-32}{9}$$

Subtract 32 from 48 to get 16.

$$\frac{16}{9}$$

Factor

$$\frac{2 ^ {4}}{3 ^ {2}} = 1\frac{7}{9} = 1.7777777777777777$$