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3\left(15x+2\right)=5x+6
Variable x cannot be equal to -\frac{6}{5} since division by zero is not defined. Multiply both sides of the equation by 3\left(5x+6\right), the least common multiple of 5x+6,3.
45x+6=5x+6
Use the distributive property to multiply 3 by 15x+2.
45x+6-5x=6
Subtract 5x from both sides.
40x+6=6
Combine 45x and -5x to get 40x.
40x=6-6
Subtract 6 from both sides.
40x=0
Subtract 6 from 6 to get 0.
x=0
Product of two numbers is equal to 0 if at least one of them is 0. Since 40 is not equal to 0, x must be equal to 0.