Solve 14/3x+5=4/3x-5/3

$$\frac { 14 } { 3 } x + 5 = \frac { 4 } { 3 } x - \frac { 5 } { 3 }$$

Solve for x

$$x=-2$$

Steps for Solving Linear Equation

Subtract \frac{4}{3}x from both sides.

$$\frac{14}{3}x+5-\frac{4}{3}x=-\frac{5}{3}$$

Combine \frac{14}{3}x and -\frac{4}{3}x to get \frac{10}{3}x.

$$\frac{10}{3}x+5=-\frac{5}{3}$$

Subtract 5 from both sides.

$$\frac{10}{3}x=-\frac{5}{3}-5$$

Convert 5 to fraction \frac{15}{3}.

$$\frac{10}{3}x=-\frac{5}{3}-\frac{15}{3}$$

Since -\frac{5}{3} and \frac{15}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{10}{3}x=\frac{-5-15}{3}$$

Subtract 15 from -5 to get -20.

$$\frac{10}{3}x=-\frac{20}{3}$$

Multiply both sides by \frac{3}{10}, the reciprocal of \frac{10}{3}.

$$x=-\frac{20}{3}\times \frac{3}{10}$$

Multiply -\frac{20}{3} times \frac{3}{10} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{-20\times 3}{3\times 10}$$

Cancel out 3 in both numerator and denominator.

$$x=\frac{-20}{10}$$

Divide -20 by 10 to get -2.

$$x=-2$$