Evaluate
\frac{141}{20}=7.05
Factor
\frac{3 \cdot 47}{2 ^ {2} \cdot 5} = 7\frac{1}{20} = 7.05
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\frac{65}{20}+\frac{76}{20}
Least common multiple of 4 and 5 is 20. Convert \frac{13}{4} and \frac{19}{5} to fractions with denominator 20.
\frac{65+76}{20}
Since \frac{65}{20} and \frac{76}{20} have the same denominator, add them by adding their numerators.
\frac{141}{20}
Add 65 and 76 to get 141.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}