Solve 13/18-1/24-(29/72+6/36)

$$\frac { 13 } { 18 } - \frac { 1 } { 24 } - ( \frac { 29 } { 72 } + \frac { 6 } { 36 } )$$

Evaluate

$$\frac{1}{9}\approx 0.111111111$$

Solution Steps

Least common multiple of 18 and 24 is 72. Convert \frac{13}{18} and \frac{1}{24} to fractions with denominator 72.

$$\frac{52}{72}-\frac{3}{72}-\left(\frac{29}{72}+\frac{6}{36}\right)$$

Since \frac{52}{72} and \frac{3}{72} have the same denominator, subtract them by subtracting their numerators.

$$\frac{52-3}{72}-\left(\frac{29}{72}+\frac{6}{36}\right)$$

Subtract 3 from 52 to get 49.

$$\frac{49}{72}-\left(\frac{29}{72}+\frac{6}{36}\right)$$

Reduce the fraction \frac{6}{36} to lowest terms by extracting and canceling out 6.

$$\frac{49}{72}-\left(\frac{29}{72}+\frac{1}{6}\right)$$

Least common multiple of 72 and 6 is 72. Convert \frac{29}{72} and \frac{1}{6} to fractions with denominator 72.

$$\frac{49}{72}-\left(\frac{29}{72}+\frac{12}{72}\right)$$

Since \frac{29}{72} and \frac{12}{72} have the same denominator, add them by adding their numerators.

$$\frac{49}{72}-\frac{29+12}{72}$$

Add 29 and 12 to get 41.

$$\frac{49}{72}-\frac{41}{72}$$

Since \frac{49}{72} and \frac{41}{72} have the same denominator, subtract them by subtracting their numerators.

$$\frac{49-41}{72}$$

Subtract 41 from 49 to get 8.

$$\frac{8}{72}$$

Reduce the fraction \frac{8}{72} to lowest terms by extracting and canceling out 8.

$$\frac{1}{9}$$

Factor

$$\frac{1}{3 ^ {2}} = 0.1111111111111111$$