Solve for x
x = \frac{40}{39} = 1\frac{1}{39} \approx 1.025641026
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Linear Equation
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\frac { 13 } { 14 } x - \frac { 2 } { 7 } = \frac { 2 } { 3 }
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\frac{13}{14}x=\frac{2}{3}+\frac{2}{7}
Add \frac{2}{7} to both sides.
\frac{13}{14}x=\frac{14}{21}+\frac{6}{21}
Least common multiple of 3 and 7 is 21. Convert \frac{2}{3} and \frac{2}{7} to fractions with denominator 21.
\frac{13}{14}x=\frac{14+6}{21}
Since \frac{14}{21} and \frac{6}{21} have the same denominator, add them by adding their numerators.
\frac{13}{14}x=\frac{20}{21}
Add 14 and 6 to get 20.
x=\frac{20}{21}\times \frac{14}{13}
Multiply both sides by \frac{14}{13}, the reciprocal of \frac{13}{14}.
x=\frac{20\times 14}{21\times 13}
Multiply \frac{20}{21} times \frac{14}{13} by multiplying numerator times numerator and denominator times denominator.
x=\frac{280}{273}
Do the multiplications in the fraction \frac{20\times 14}{21\times 13}.
x=\frac{40}{39}
Reduce the fraction \frac{280}{273} to lowest terms by extracting and canceling out 7.
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