Solve 128/250=(4/5)^2

$$\frac { 128 } { 250 } = ( \frac { 4 } { 5 } ) ^ { 2 }$$

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Solution Steps

Reduce the fraction \frac{128}{250} to lowest terms by extracting and canceling out 2.

$$\frac{64}{125}=\left(\frac{4}{5}\right)^{2}$$

Calculate \frac{4}{5} to the power of 2 and get \frac{16}{25}.

$$\frac{64}{125}=\frac{16}{25}$$

Least common multiple of 125 and 25 is 125. Convert \frac{64}{125} and \frac{16}{25} to fractions with denominator 125.

$$\frac{64}{125}=\frac{80}{125}$$

Compare \frac{64}{125} and \frac{80}{125}.

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