Solve 12-3y/6=y-4/2

$$\frac { 12 - 3 y } { 6 } = \frac { y - 4 } { 2 }$$

Solve for y

$$y=4$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6, the least common multiple of 6,2.

$$12-3y=3\left(y-4\right)$$

Use the distributive property to multiply 3 by y-4.

$$12-3y=3y-12$$

Subtract 3y from both sides.

$$12-3y-3y=-12$$

Combine -3y and -3y to get -6y.

$$12-6y=-12$$

Subtract 12 from both sides.

$$-6y=-12-12$$

Subtract 12 from -12 to get -24.

$$-6y=-24$$

Divide both sides by -6.

$$y=\frac{-24}{-6}$$

Divide -24 by -6 to get 4.

$$y=4$$