Solve 11/8+7/40+1/5

$$\frac { 11 } { 8 } + \frac { 7 } { 40 } + \frac { 1 } { 5 }$$

Evaluate

$$\frac{7}{4}=1.75$$

Solution Steps

Least common multiple of 8 and 40 is 40. Convert \frac{11}{8} and \frac{7}{40} to fractions with denominator 40.

$$\frac{55}{40}+\frac{7}{40}+\frac{1}{5}$$

Since \frac{55}{40} and \frac{7}{40} have the same denominator, add them by adding their numerators.

$$\frac{55+7}{40}+\frac{1}{5}$$

Add 55 and 7 to get 62.

$$\frac{62}{40}+\frac{1}{5}$$

Reduce the fraction \frac{62}{40} to lowest terms by extracting and canceling out 2.

$$\frac{31}{20}+\frac{1}{5}$$

Least common multiple of 20 and 5 is 20. Convert \frac{31}{20} and \frac{1}{5} to fractions with denominator 20.

$$\frac{31}{20}+\frac{4}{20}$$

Since \frac{31}{20} and \frac{4}{20} have the same denominator, add them by adding their numerators.

$$\frac{31+4}{20}$$

Add 31 and 4 to get 35.

$$\frac{35}{20}$$

Reduce the fraction \frac{35}{20} to lowest terms by extracting and canceling out 5.

$$\frac{7}{4}$$

Factor

$$\frac{7}{2 ^ {2}} = 1\frac{3}{4} = 1.75$$